Serum total antioxidant capacity and enzymatic defence of dogs with chronic heart failure and atrial fibrillation: a preliminary study
Marcin Michałek , Aleksandra Tabiś , Agnieszka Noszczyk-Nowak
AbstractIntroduction: Atrial fibrillation may potentially contribute to oxidative stress to a greater extent than chronic heart failure. The aim of the study was to compare the serum total antioxidant capacity and enzymatic antioxidant defence of dogs with chronic heart failure and atrial fibrillation with those of subjects with chronic heart failure and sinus rhythm and healthy controls. Material and Methods: A total of 33 dogs were divided into three groups: dogs with chronic heart failure and atrial fibrillation (CHF + AF; n = 12), chronic heart failure and sinus rhythm (CHF + SR; n = 9), and healthy controls (n = 12). Serum total antioxidant capacity (TAC), serum CuZn-superoxide dismutase (SOD) and catalase, and plasma glutathione peroxidase (GPx) activity were determined. Results: SOD activity and serum TAC were significantly lower in the study groups than in control animals. Catalase activity was significantly higher and plasma GPx activity significantly lower in dogs with CHF + AF compared with the CHF + SR and control dogs. Conclusion: The results suggest that chronic heart failure in dogs significantly impacts the serum TAC and the antioxidant enzymatic defence, while plasma GPx activity is markedly lower in dogs with chronic heart failure and atrial fibrillation. The role of that imbalance needs further investigation.
|Journal series||Journal of Veterinary Research, [Bulletin of the Veterinary Institute in Pulawy, Journal of Veterinary Research (Poland)], ISSN 2450-7393, e-ISSN 2450-8608, (N/A 40 pkt)|
|Publication size in sheets||0.5|
|Keywords in English||dogs, cardiology, atrial fibrillation, chronic heart failure, oxidative stress|
|License||Journal (articles only); published final; ; before publication|
|Score||= 40.0, 10-05-2021, ArticleFromJournal|
|Publication indicators||= 0; = 0; : 2018 = 0.501; : 2019 = 1.039 (2) - 2019=1.009 (5)|
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